Q. A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5 m in the first second and a distance of 2 m in the third second. The force acting on the body is

Solution:

Using $S_n = u +\dfrac{a}{2}(2n - 1), $ we get $5 = u + \dfrac{a}{2}(2 \times 1 - 1)$ i.e. 10 = 2u + a and
$2 = u + \dfrac{a}{2} (2 \times 3 - 1) $ i.e. 4 = 2u +5a
Using these equations, we have
4a = - 6 i.e. $a = - \dfrac{6}{4} = - \dfrac{3}{2} \, m \, s^{-2}$
Then. force. |F| = ma = 4 $\times \dfrac{3}{2}$ = 6 N

You must select option to get answer and solution

Physics Most Viewed Questions

2. To have large selectivity in a series LCR circuit

COMEDK 2006 Alternating Current

7. The hot wire ammeter measures

Rajasthan PMT 2004 Alternating Current