Q. A ray of light along $x+\sqrt 3 \, y=\sqrt 3$ gets reflected upon reaching X-axis, the equation of the reflected ray is

Solution:

Take any point B (0,1) on given line.
Equation of AB' is
$\, \, \, \, \, \, \, \, \, \, \, \, y-0= \frac {-1-0}{0-\sqrt 3}(x-\sqrt 3)$
$\Rightarrow \, \, \, \, \, \, \, \, -\sqrt 3y=-x+ \sqrt 3$
$\Rightarrow \, \, \, \, \, \, \, \, x- \sqrt 3 y= \sqrt 3$
$\Rightarrow \, \, \, \, \, \, \, \, \sqrt 3y=x- \sqrt 3$

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