Q. For the circuit shown below, the current through the Zener diode is :

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Assuming zener diode doesnot undergo breakdown, current in circuit = $\frac{120}{15000} = 8mA$
$\therefore$ Voltage drop across diode = 80 V > 50 V.
The diode undergo breakdown.
Current is $R_1 = \frac{70}{5000} = 14 mA$
Current is $R_2 = \frac{50}{10000} = 5 mA$
$\therefore$ Current through diode = 9mA

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