# Q. In the circuit shown, the currents $i_1$ and $i_2$ are ___________

KCET KCET 2011Current Electricity

Solution:

## $R\:=\:\frac{12\:\times 4}{12\:+\:4}\:+\:2\:=\:5\:\Omega \:$ $\:\:I\:=\:\frac{E}{R\:+\:r}=\:\frac{12}{6}\:=\:2\:A\:$ $\:\:\:I_1\:+\:I_2\:=\:2A\:$ $\:I\:\propto \frac{1}{R}\:\therefore I_1\:=\:0.5A,\:I_{2\:}=\:1.5A$

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