# Q. At a given instant, say t = 0, two radioactive substances A and B have equal activities. The ratio $\frac{R_B}{R_A}$ of their activities after time t itself decays with time t as $e^{-3t}$ . [f the half-life of A is $m_2$, the half-life of B is :

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Solution:

## Half life of $A = \ell n^2$ $t_{1/2} = \frac{\ell n2}{\lambda}$ $\lambda_A = 1$ at $t = 0 \; R_A = R_B$ $N_A e^{- \lambda AT} = N_B e^{-\lambda BT}$ $N_A = N_B$ at $t = 0$ at $t = t \; \frac{R_B}{R_A} = \frac{N_0 e^{\lambda_Bt}}{N_0 e^{- \lambda_A t}}$ $e^{-(\lambda_B - \lambda_A)t} = e^{-t}$ $\lambda_B - \lambda_A = 3$ $\lambda_B = 3 + \lambda_A = 4$ $t_{1/2} = \frac{\ell n2}{\lambda_B} = \frac{\ell n 2}{4}$

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