# Q. The magnitude of $I$ in ampere unit is

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Solution:

## All the resistances are in paralleI order, so voitage across them will be equal. $\therefore 60I = (15 + 5)I_1$ $\Rightarrow 60I = 20I_1$ $\Rightarrow I_1 = 3I$ Again $(15 + 5)I_1 = 10(1 - I - I_1)$ $\Rightarrow 2I_1 = 1 - I - I_1$ $\Rightarrow 2(3I) = 1 - I - 3I$ $\Rightarrow 6I + 4I = 1$ $\Rightarrow 10I = 1$ $\therefore I = \frac{1}{10} = 0.1 A$

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