Solution:

All the resistances are in paralleI order, so voitage across them will be equal.
$ \therefore 60I = (15 + 5)I_1 $
$ \Rightarrow 60I = 20I_1 $
$ \Rightarrow I_1 = 3I $
Again $ (15 + 5)I_1 = 10(1 - I - I_1) $
$ \Rightarrow 2I_1 = 1 - I - I_1 $
$ \Rightarrow 2(3I) = 1 - I - 3I $
$ \Rightarrow 6I + 4I = 1 $
$ \Rightarrow 10I = 1 $
$ \therefore I = \frac{1}{10} = 0.1 A $

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