Q. A conducting circular loop made of a thill wire, has area $3.5 \times 10^{-3} m^2$ and resistance $10 \Omega$ . It is placed perpendicular to a time dependent magnetic field $B(t) = (0.4T) \sin(50 \pi t)$. The field is uniform in space. Then the net charge flowing through the loop during t = 0 s and t = 10 ms is close to:

Solution:

$Q = \frac{\Delta \phi}{R} = \frac{1}{10} A\left(B_{f} -B_{i}\right) = \frac{1}{10} \times3.5 \times10^{-3} \left(0.4 \sin \frac{\pi}{2} -0\right) $
$ = \frac{1}{10} \left(3.5 \times10^{-3}\right)\left(0.4 - 0\right)$ $ = 1.4 \times10^{-4} = 0.14\, mC $

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