Q. A hydrogen atom, initially in the ground state is excited by absorbing a photon of wavelength 980$\mathring A $. The radius of the atom in the excited state, it terms of Bohr radius $a_0$, will be : ($h_c$ = 12500 eV - $\mathring A $)

Solution:

Energy of photon $ = \frac{12500}{980} = 12.75 eV$
$\therefore$ Electron will excite to n= 4
Since $'R' \propto n^2$
$\therefore$ Radius of atom will be $16a_0$

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