# Q. Which of the following solutions will have pH close to 1.0 ?

IIT JEEIIT JEE 1992Equilibrium

Solution:

## 75 mL $\frac{ M}{ 5 }$ HCl = 15 mmol HCl 25 mL $\frac{ M}{ 5 }$ NaOH = 5 mmol NaOH After neutralisation, 10 mmol HC1 will be remaining in 100 mL of solution. Molarity of HCl in the final solution $\, \, \, \, = \frac{ 10 }{ 100 } = 0.10$ pH $= - log [H^+ ]$ $\, \, \, \, \, = - \log (0.10) = 1.$

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