Q. Which of the following solutions will have pH close to 1.0 ?

Solution:

75 mL $ \frac{ M}{ 5 } $ HCl = 15 mmol HCl
25 mL $ \frac{ M}{ 5 } $ NaOH = 5 mmol NaOH
After neutralisation, 10 mmol HC1 will be remaining in 100 mL of solution. Molarity of HCl in the final solution
$ \, \, \, \, = \frac{ 10 }{ 100 } = 0.10 $
pH $= - log [H^+ ]$
$ \, \, \, \, \, = - \log (0.10) = 1.$

You must select option to get answer and solution