Q. In the cube of side 'a' shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be:

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Solution:

$\vec{r}_{g} = \frac{a}{2} \hat{i} + \frac{a}{2} \hat{k} $
$ \vec{r}_{H} =\frac{a}{2} \hat{j} + \frac{a}{2} \hat{k} $
$\vec{ r}_{H} - \vec{r}_{g} = \frac{a}{2} \left(\hat{j} - \hat{i}\right) $

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