Q. A closed organ pipe has a fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be : (Assume that the highest frequency a person can hear is 20,000 Hz)

Solution:

For closed organ pipe, resonate frequency is odd multiple of fundamental frequency.
$\therefore \; (2n + 1) \; f_0 \le 20,000$
($f_o$ is fundamental frequency = 1.5 KHz)
$\therefore $ n = 6
$\therefore$ Total number of overtone that can be heared is 7. (0 to 6).

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