# Q. If the dimensions of a physical quantity are given by $[M^aL^bT^c]$, then the physical quantity will be

AIPMTAIPMT 2009Physical World, Units and Measurements

Solution:

## Pressure,$P=\frac{force}{area}=\frac{mass \, \times\, acceleration}{area}$ $\therefore \, \, [P]=\frac{M^1LT^{-2}}{L^2}=[M^1L^{-1}T^{-2}]=M^aL^bT^c$. $\therefore$ a = 1,b = -1, c = -2.

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