# Q. In the given network, the value of $C$, so that an equivalent capacitance between $A$ and $B$ is $3\mu F$, is...........

KCET KCET 2011Electrostatic Potential And Capacitance

Solution:

## $3\:=\:\frac{\frac{16}{5}\:C}{\frac{16}{5}\:+C}\:\therefore C\:=\:48\:\mu F$

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