Q. Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is $10^{19} m^{-3}$ and their mobility is $1.6 m^2/(V.s)$ then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to:


$j = \sigma E = nev_{d} $
$ \sigma =ne \frac{v_{d}}{E} $
$=ne \mu$
$ \frac{1}{\sigma} = \rho = \frac{1}{n_{e}e\mu_{e}} = \frac{1}{10^{19} \times1.6 \times10^{-19} \times1.6} $
$ = 0.4 \Omega m$

You must select option to get answer and solution

Questions from JEE Main 2019

Physics Most Viewed Questions

6. The spectrum of an oil flame is an example for ...........

KCET 2010 Dual Nature Of Radiation And Matter