Q. A non-volatile solute, ‘A’ tetramerises in water to the extent of 80%. 2.5 g of ‘A’ in 100 g of water, lowers the freezing point by 0.3 °C. the molar mass of Å in mol L-1 is (Kf for water = 1.86 K kg mol-1)

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Solution:

$\alpha=\frac{80}{100}=0.8$ $\alpha=\frac{1-i}{1-\frac{1}{n}}=\frac{1-i}{1-\frac{1}{4}}$ $0.8=\frac{1-i}{\frac{3}{4}}$ $i=0.4$ $\Delta T_{f}=0.3$ $\Delta T_{f}=\frac{i\times k_{f}\times w_{2}\times1000}{M_{2}\times100}$ $M_{2}=\frac{0.4\times1.86\times2.5\times10}{0.3}$ $M_{2}=62 \, g\, mol^{-1}$

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