Q. A mixture of 2 moles of helium gas (atomic mass = 4 u), and 1 mole of argon gas (atomic mass = 40 u) is kept at 300 K in a container. The ratio of their rms speeds $\left[\frac{V_{rms}\left(\text{helium}\right)}{V_{rms} ((\text{argon})}\right],$is close to :

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Solution:

$\frac{V_{rms} \left(He\right)}{V_{rms}\left(Ar\right)} = \sqrt{\frac{M_{Ar}}{M_{He}}} = \sqrt{\frac{40}{4}} = 3.16$

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