Q. A block of mass m, lying on a smooth horizontal surface, is attached to a spring (of negligible mass) of spring constant k. The other end of the spring is fixed, as shown in the figure. The block is initally at rest in its equilibrium position. If now the block is pulled with a constant force F, the maximum speed of the block is :

Physics Question Image


Maximum speed is at mean position (equilibrium). F = kx
$x = \frac{F}{k}$
$ W_{F} + W_{sp} = \Delta KE $
$ F\left(x\right) - \frac{1}{2} kx^{2} = \frac{1}{2} mv^{2} -0$
$ F\left(\frac{F}{k}\right)- \frac{1}{2} k \left(\frac{F}{k}\right)^{2} = \frac{1}{2} mv^{2} $
$ \Rightarrow v_{max } = \frac{F}{\sqrt{mk}}$

You must select option to get answer and solution

Questions from JEE Main 2019

Physics Most Viewed Questions

7. The spectrum of an oil flame is an example for ...........

KCET 2010 Dual Nature Of Radiation And Matter