Q. A copper wire is stretched to make it 0.5% longer. The percentage change in its electrical resistance if its volume remains unchanged is:

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Solution:

$R = \frac{\rho\ell}{A}$ and volume (V) = A$\ell$. $R = \frac{\rho\ell^{2}}{V}$ $\Rightarrow \frac{\Delta R}{R} = \frac{2\Delta\ell}{\ell} = 1\%$

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