Q. The top of a water tank is open to air and its water level is maintained. It is giving out $0.74 m^3$ water per minute through a circular opening of 2 cm radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to :


In flow volume = outflow volume
$\Rightarrow \frac{0.74}{60} = \left(\pi \times4 \times10^{-4}\right) \times\sqrt{2gh} $
$ \Rightarrow \sqrt{2gh} = \frac{74 \times100}{240 \pi} $
$ \Rightarrow \sqrt{2gh} \frac{740}{24\pi} $
$ \Rightarrow 2gh = \frac{740 \times740 }{24 \times24\times10} \left(\pi^{2} = 10\right)$
$ \Rightarrow h = \frac{74 \times74}{2 \times24 \times24} $
$ \Rightarrow h \approx 4.8 m $

You must select option to get answer and solution

Questions from JEE Main 2019

Physics Most Viewed Questions

6. The spectrum of an oil flame is an example for ...........

KCET 2010 Dual Nature Of Radiation And Matter