Q. A uniform metallic wire has a resistance of $18 \; \Omega$ and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is :

Solution:

$R_{eq}$ between any two vertex will be
$\frac{1}{R_{eq}} = \frac{1}{12} + \frac{1}{6} \; \Rightarrow \; R_{eq} = 4 \Omega$

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