Q. The position co-ordinates of a particle moving in a 3-D coordinate system is given by
$x = a \; \cos \omega t$
$y = a \; \sin \omega t$
and $z = a \omega t$
The speed of the particle is :

Solution:

$v_{x} = - a \omega \sin\omega t \Rightarrow v_{y} = a \omega \cos\omega t $
$ v_{z} = a \omega \Rightarrow v = \sqrt{v^{2}_{x} + v^{2}_{y} +v^{2}_{z}} $
$ v = \sqrt{2} a \omega$

You must select option to get answer and solution

Questions from JEE Main 2019

Physics Most Viewed Questions

8. The spectrum of an oil flame is an example for ...........

KCET 2010 Dual Nature Of Radiation And Matter