## Questions from KCET 2018

## 4. For the probability distribution given by

$X = x_i$ | 0 | 1 | 2 |

$P_i$ | $\frac{25}{36}$ | $\frac{5}{18}$ | $\frac{1}{36}$ |

the standard deviation $(\sigma)$ is

$X = x_i$ | 0 | 1 | 2 |

$P_i$ | $\frac{25}{36}$ | $\frac{5}{18}$ | $\frac{1}{36}$ |

the standard deviation $(\sigma)$ is