Q. A 2 W carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is :

Solution:

$P = i^2R$.
$\therefore$ for $i_{max}$, R must be minimum from color coding $R = 50 \times 10^2 \Omega$
$\therefore \; i_{max} = 20mA$

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