Q. When the switch S, in the circuit shown, is closed, then the value of current i will be :

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Let voltage at C = xv
KCL : $i_1 + i_2 = i$
$\frac{20-x}{2} + \frac{10-x}{4} = \frac{x-0}{2}$
$ \Rightarrow x = 10 $
and i = 5 amp.

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