Q. A liquid of density $\rho$ is coming out of a hose pipe of radius a with horizontal speed v and hits a mesh. 50% of the liquid passes through the mesh unaffected. 25% looses all of its momentum and 25% comes back with the same speed. The resultant pressure on the mesh will be :

Solution:

Momentum per second carried by liquid per second is $\rho av^2$
net force due to reflected liquid = $2 \times [ \frac{1}{4} \rho av^2 ]$
net force due to stopped liquid = $\frac{1}{4} \rho av^2$
Total force = $\frac{3}{4} \rho av^2$
net pressure = $\frac{3}{4} \rho v^2$

You must select option to get answer and solution

Questions from JEE Main 2019

Physics Most Viewed Questions

8. The spectrum of an oil flame is an example for ...........

KCET 2010 Dual Nature Of Radiation And Matter