Q. A solid metal cube of edge length 2 cm is moving in a positive y direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z-direction. The potential difference between the two faces of the cube perpendicular to the x-axis, is :

Solution:

Potential difference between two faces perpendicular to x-axis will be $\ell . (\vec{V} \times \vec{B} ) = 12 m V $

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